Don’t trust me on this, cause it’s been a while since I’ve done this stuff, but I think it’d be 37.5C because if there were equal amounts of water the temperature would be halfway in between 60C and 30C (45C), but because there’s half as much of the 60C, it’d be closer to 30C, by half of the difference between 30C and 60C. Again, don’t take my word for it, but if I remember right, that’s what it should be. Good luck!
Your equation should be set like this. Q_lost = Q_gained. Think of it as the 30 degree water gaining the heat that the 60 degree water is losing. SO:
Q=MC(Tf – Ti)
M = Mass of waterC= Specific Heat of WaterTf = Final temperature of waterTi = Initial temperature of water
Water has a mass of 1g/ml Specific heat of water is 1 cal/gram * C
(50)(1.0)(60 – Tf) = (100)(1.0)(Tf – 30)
(50)(60 – Tf) = (100)(Tf – 30)
3000 – 50Tf = 100Tf – 3000
6000 – 50Tf = 100Tf
6000 = 150Tf
Tf = 40 degrees Celsius.
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